2 * L + 4*w = 800
so
L = 400 - 2w
A = L * w
A = (400 -2w)w
A = -2 w^2 +400 w
dA/dw = 0 at max
= -2 w + 200
w = 100
L = 400 -200 = 200
A rectangular field is to be enclosed by a fence and divided into three lots by fences parallel to one of the sides. Find the dimensions of the largest field that can be enclosed with 800 feet of fencing.
Help me please!!!!!!!!!!! THANK YOU
2 answers
thanks