ahmed throws a ball at initial velocity of 36 meter per second.assuming the ball is caught at the same height at which it was released. calculate the maximum distance the ball can reach.

Question

Henry · Accepted Answer

a football thrown at 45o has max range: Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.

Anonymous · Answer

U Coll out answer please

Anonymous · Answer

Ahmed throws a ball at an initial velocity of 25m/s.calculate the maximum distance the ball can reach assuming the ball is caught at the same height at which it was released.