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A quarterback throws a pass at an angle of 40 degrees above the horizontal with an initial speed of 20 m/s. The ball is caught...Asked by Jose Luis
A quarterback throws a pass at an angle of 40 degrees above the horizontal with an initial speed of 20 m/s. The ball is caught by the receiver 2.55 seconds later. Determine horizontal velocity, vertical initial velocity, the distance ball was thrown, and maximum height of the ball?
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Answered by
Steve
well, the vertical position at time t is
y(t) = 20 sin40° t - 4.9t^2
= 12.86t - 4.9t^2
I think that should get you started ok.
y(t) = 20 sin40° t - 4.9t^2
= 12.86t - 4.9t^2
I think that should get you started ok.