Vo = 20m/s[40o].
Xo = 20*Cos40 = 15.3 m/s.
Yo = 20*sin40 = 12.9 m/s.
Dx = Xo*t = 15.3m/s * 2.55s. = 39 m.
h = Yo*Tr + 0.5g*Tr^2
Tr = 2.55/2 = 1.275 s. = Rise time.
g = -9.8 m/s^2.
A quarterback throws a pass at an angle of 40 degrees above the horizontal with an initial speed of 20 m/s. The ball is caught by the receiver 2.55 seconds later. Determine horizontal velocity, vertical initial velocity, the distance ball was thrown, and maximum height of the ball. Can you do it? Show me...
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