P(~yellow) = 1 - P(yellow)
multiply for each draw (assuming that there are enough M&Ms that drawing a few does not affect the probabilities)
1 minus the answer to part A.
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]
If you randomly select two peanut M&M’s, compute that probability that neither of them are yellow.
If you randomly select two peanut M&M’s, compute that probability that at least one of them is yellow.
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