According to Masterfoods, the company that manufactures M&M’s,

Question

12% of peanut M&M’s are brown,
15% are yellow,
12% are red,
23% are blue,
23% are orange, and
15% are green.

Compute the probability that a randomly selected peanut M&M is not green.



Compute the probability that a randomly selected peanut M&M is red or orange.



Compute the probability that two randomly selected peanut M&M’s are both green.



If you randomly select six peanut M&M’s, compute that probability that none of them are green.



If you randomly select six peanut M&M’s, compute that probability that at least one of them is green.

I ONLY need the formula for the last one. I already got the first four questions, but the last one I can't seem to get.

Thanks in advance!

Answer 1

that will be 1 - P(none green) = 1 - 0.85^6