△ABC has vertices A(−6,5), B(−2,5), and C(−6,0).

What is the area of △ABC?
20 units2
9 units2
14 units2
10 units2

im not sure what it is can someone help????

4 answers

sketch it out : )
Then it is base length x height and then divided by 2
Once you have the picture you can find the measurements.
The base length is from -6 to -2, which is 4 units...
The height is from (-6,0) up to (-6,5)
Hope this helps : )
(AB)^2 = (-2+6)^2 + (5-5)^2 = 16.
AB = 4.

(BC)^2 = (-6+2)^2 + (0-5)^2 = 41,
BC = sqrt41. = 6.4.

(AC)^2 = (-6+6)^2 + (0-5)^2 = 25,
AC = 5.

(5/2)^2 + h^2 = 6.4^2,
h = 5.89.

A = hb/2 = 5.89*5/2 = 14.7.
so what is the answer?