( copy/ orginal) = 10/3
(10/3)=(copy perimeter)/(orig.perimeter)
(10/3)=(36/X)
cross multiply and you get
10x=108 then x= 10 4/5 =10.8
x=perimeter of org.
triangle
Do the same with part b but this time it's area.
(10/3)=(48/x) ===> x= 14 2/5 =14.4
A triangle is enlarged by a scale factor of 10/3.
a) If the perimeter of the copy is 36 meters, find the perimeter of the original triangle using the proportion 10/3.
b) If the area of the copied triangle is 48 meters squared, use a proportion to find the area of the original triangle.
Please HELP me! I don't really know how I can solve this...
2 answers
Samantha, your second part is not correct
The area of similar figures is proportional to the square of their sides. Since perimeter is a function of the sides you last line should have been
(10/3)2 =(48/x) ===> x= 4.32
The area of similar figures is proportional to the square of their sides. Since perimeter is a function of the sides you last line should have been
(10/3)2 =(48/x) ===> x= 4.32
2 answers