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suppose you dilate a triangle using the scale factor of 1/3. The original side lengths of the triangle measure 11,9, and 28 inc...Question
                Suppose you dilate a triangle using the scale factor of 1/3. The original side lengths of the triangle measure 11,9 and 28 inches. What is the perimeter of the dilated triangle?
perimeter = _ in
            
        perimeter = _ in
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                    Answered by
            GPT-4o mini
            
    To find the perimeter of the dilated triangle, we first need to calculate the new side lengths after applying the dilation scale factor of \( \frac{1}{3} \).
The original side lengths of the triangle are:
- Side 1: 11 inches
- Side 2: 9 inches
- Side 3: 28 inches
Now, we will multiply each side length by the scale factor:
1. New Side 1:
\[
11 \times \frac{1}{3} = \frac{11}{3} \text{ inches}
\]
2. New Side 2:
\[
9 \times \frac{1}{3} = 3 \text{ inches}
\]
3. New Side 3:
\[
28 \times \frac{1}{3} = \frac{28}{3} \text{ inches}
\]
Next, we calculate the perimeter of the dilated triangle by adding the new side lengths:
\[
\text{Perimeter} = \frac{11}{3} + 3 + \frac{28}{3}
\]
To add these, we first express 3 as a fraction with a common denominator of 3:
\[
3 = \frac{9}{3}
\]
Now we can add the fractions:
\[
\text{Perimeter} = \frac{11}{3} + \frac{9}{3} + \frac{28}{3}
\]
\[
\text{Perimeter} = \frac{11 + 9 + 28}{3} = \frac{48}{3} = 16 \text{ inches}
\]
Therefore, the perimeter of the dilated triangle is:
\[
\text{perimeter} = 16 \text{ in}
\]
    
The original side lengths of the triangle are:
- Side 1: 11 inches
- Side 2: 9 inches
- Side 3: 28 inches
Now, we will multiply each side length by the scale factor:
1. New Side 1:
\[
11 \times \frac{1}{3} = \frac{11}{3} \text{ inches}
\]
2. New Side 2:
\[
9 \times \frac{1}{3} = 3 \text{ inches}
\]
3. New Side 3:
\[
28 \times \frac{1}{3} = \frac{28}{3} \text{ inches}
\]
Next, we calculate the perimeter of the dilated triangle by adding the new side lengths:
\[
\text{Perimeter} = \frac{11}{3} + 3 + \frac{28}{3}
\]
To add these, we first express 3 as a fraction with a common denominator of 3:
\[
3 = \frac{9}{3}
\]
Now we can add the fractions:
\[
\text{Perimeter} = \frac{11}{3} + \frac{9}{3} + \frac{28}{3}
\]
\[
\text{Perimeter} = \frac{11 + 9 + 28}{3} = \frac{48}{3} = 16 \text{ inches}
\]
Therefore, the perimeter of the dilated triangle is:
\[
\text{perimeter} = 16 \text{ in}
\]
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