To find the perimeter of the dilated triangle, we first need to calculate the new side lengths after applying the dilation scale factor of \( \frac{1}{3} \).
The original side lengths of the triangle are:
- Side 1: 11 inches
- Side 2: 9 inches
- Side 3: 28 inches
Now, we will multiply each side length by the scale factor:
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New Side 1: \[ 11 \times \frac{1}{3} = \frac{11}{3} \text{ inches} \]
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New Side 2: \[ 9 \times \frac{1}{3} = 3 \text{ inches} \]
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New Side 3: \[ 28 \times \frac{1}{3} = \frac{28}{3} \text{ inches} \]
Next, we calculate the perimeter of the dilated triangle by adding the new side lengths:
\[ \text{Perimeter} = \frac{11}{3} + 3 + \frac{28}{3} \]
To add these, we first express 3 as a fraction with a common denominator of 3:
\[ 3 = \frac{9}{3} \]
Now we can add the fractions: \[ \text{Perimeter} = \frac{11}{3} + \frac{9}{3} + \frac{28}{3} \] \[ \text{Perimeter} = \frac{11 + 9 + 28}{3} = \frac{48}{3} = 16 \text{ inches} \]
Therefore, the perimeter of the dilated triangle is: \[ \text{perimeter} = 16 \text{ in} \]