A trapezium ABCD is such that AB//CD and the perpendicular from A to CD is 40cm.if AB=20cm,DA=50cm and CD=60cm.calculate the (i)area of the trapezium (ii)<BCD.pls help me with (ii)

Question

solution so far.(i)area=1/2(20 60)40
=1600cm^2

Answer 1

Let P be the base of the perpendicular from A, and Q the base of the perpendicular from B.

APD is a 30-40-50 right triangle.
So, CD=30, making AP=30 and QD=10.

Triangle CQB thus has height 40 and leg CQ=50. So, tan(BCD) = 4/5