A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point) Responses 75% 75% 50% 50% 0% 0% 25%

Answer 1

To determine the probability of getting a short, homozygous pea plant (tt) from a cross between two heterozygous tall pea plants (Tt), we can set up a Punnett square.

1. The possible gametes (alleles) from each parent (Tt) are:

   • Parent 1 (Tt): T, t
   • Parent 2 (Tt): T, t

2. The Punnett square would look like this:

| | T | t | |---|---|---| | T | TT | Tt | | t | Tt | tt |

3. Now, let's fill in the Punnett square:

   • The top row represents the alleles from Parent 1, and the left column represents the alleles from Parent 2.
   • The combinations yield:
   • TT (homozygous tall)
   • Tt (heterozygous tall)
   • Tt (heterozygous tall)
   • tt (homozygous short)

4. The offspring genotypes from the Punnett square are:

   • 1 TT (25%)
   • 2 Tt (50%)
   • 1 tt (25%)

From the Punnett square, we see that there is 1 tt genotype out of 4 total genotypes.

Probability of tt (short, homozygous) = 1/4 = 25%

The correct answer is 25%.