A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point)

Question

Responses

50%
50%

25%
25%

0%
0%

75%

Answer 1

To determine the probability that the offspring from a cross between two heterozygous tall pea plants (Tt) will be a short homozygous pea plant (tt), we can use a Punnett square.

1. Identify the genotypes of the parents:
   Both parents are Tt (heterozygous tall).

2. Set up the Punnett square:
   The alleles from one parent (Tt) are on the top, and the alleles from the other parent (Tt) are on the side:

           T       t
       ----------------
     T |   TT    |  Tt  |
       ----------------
     t |   Tt    |  tt  |
       ----------------
   

3. Determine the genotypes of the offspring:
   From the Punnett square, we have the following combinations:

   • TT (tall)
   • Tt (tall)
   • Tt (tall)
   • tt (short)

4. Count the results:

   • TT = 1
   • Tt = 2
   • tt = 1

5. Calculate the probability of tt:
   There is 1 offspring that is tt out of a total of 4 offspring, so the probability is: \( \frac{1}{4} = 25% \)

Therefore, the correct response is:

25%