A tall, heterozygous pea plant (Tt) is crossed with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt).(1 point)

Question

Responses

50%
50%

0%
0%

25%
25%

75%

Answer 1

To determine the probability of obtaining a short, homozygous pea plant (tt) from a cross between two tall, heterozygous pea plants (Tt), we can use a Punnett square.

1. Set up the Punnett square with the gametes from each parent:

   • One parent (Tt) can produce gametes: T and t
   • The other parent (Tt) can also produce gametes: T and t

   The Punnett square looks like this:

          T       t
       ______________
    T |   TT     |   Tt   |
       |__________|_______|
    t |   Tt     |   tt   |
       |__________|_______|
   

2. Now, let's analyze the possible genotypes of the offspring:

   • TT: 1 square
   • Tt: 2 squares
   • tt: 1 square

3. From this, the genotypic ratio of the offspring is:

   • TT: 1
   • Tt: 2
   • tt: 1

4. The probability of the offspring being short and homozygous (tt) is:

   • There is 1 tt out of a total of 4 possible genotypes.

Thus, the probability is \( \frac{1}{4} = 25% \).

So the correct response is:

25%