To determine the probability of obtaining a short, homozygous pea plant (tt) from a cross between two tall, heterozygous pea plants (Tt), we can set up a Punnett square.
For a cross of Tt and Tt:
T t
----------------
T | TT | Tt |
----------------
t | Tt | tt |
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The possible genotypes of the offspring from this cross are:
- TT (homozygous tall)
- Tt (heterozygous tall)
- Tt (heterozygous tall)
- tt (homozygous short)
Now let's count the genotypes:
- 1 TT
- 2 Tt
- 1 tt
From this, we can see that there is 1 tt out of 4 total genotypes.
To find the probability of the short homozygous offspring (tt):
\[ \text{Probability of } tt = \frac{\text{Number of } tt}{\text{Total number of offspring}} = \frac{1}{4} = 25% \]
So, the probability that the offspring is a short, homozygous pea plant (tt) is 25%.