In this scenario, we have two tall, heterozygous pea plants. We can denote the tall allele (dominant) as "T" and the short allele (recessive) as "t." Since both plants are heterozygous, their genotype is Tt.
To set up a Punnett square, we'll write one parent's alleles along the top and the other parent's alleles along the side:
T t
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T | TT | Tt |
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t | Tt | tt |
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From this Punnett square, we can see the possible genotypes of the offspring:
- TT (homozygous tall) - 1 out of 4 (25%)
- Tt (heterozygous tall) - 2 out of 4 (50%)
- tt (homozygous short) - 1 out of 4 (25%)
Now, to find the probability that the offspring is a tall, homozygous pea plant (TT), we find that there is 1 TT out of 4 total squares.
Thus, the probability that the offspring is a tall, homozygous pea plant is 25%.
Final Answer: 25%
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