A tall, heterozygous pea plant is cross-pollinated with another tall, heterozygous pea plant. Use a Punnett square to determine the probability that the offspring is a tall, homozygous pea plant.(1 point) Responses 0% 0% 75% 75% 50% 50% 25% 25%

Answer 1

To determine the probability of obtaining a tall, homozygous pea plant from a cross between two tall, heterozygous pea plants, we can use a Punnett square.

Let's denote:

• "T" for the tall allele (dominant)
• "t" for the short allele (recessive)

Since both parent plants are heterozygous, their genotypes are Tt.

Now, we set up the Punnett square:

          T         t
        ----------------
     T |   TT    |   Tt   |
        ----------------
     t |   Tt    |   tt   |
        ----------------

In the Punnett square, we see the following genotypes of the offspring:

1. TT (homozygous tall)
2. Tt (heterozygous tall)
3. Tt (heterozygous tall)
4. tt (homozygous short)

From this Punnett square, we can summarize the results:

• 1 TT (homozygous tall)
• 2 Tt (heterozygous tall)
• 1 tt (homozygous short)

So, there are 4 total offspring possibilities:

• 1 TT out of 4 is homozygous tall.

To find the probability of the offspring being a tall, homozygous pea plant (TT), we take:

\[ \text{Probability of TT} = \frac{\text{Number of TT offspring}}{\text{Total offspring}} = \frac{1}{4} = 25% \]

Therefore, the probability that the offspring is a tall, homozygous pea plant is 25%.