the horizontal speed is 5m/0.5s = 10 m/s
Now just use the fact that PE lost = KE gained, so
gh = 1/2 v^2
plug in your numbers and solve for h. That is the height of the slide above where the person shot out.
So now add to that the distance the person dropped in 0.5s (s = 1/2 gt^2)
A swimmer on a water-slide ,starts from rest at the top of the slide and leaves the end of the slide traveling horizontally. One person hits the water 5.00 m from the end of the slide in a time of 0.500 s after leaving the slide. Ignoring friction and air resistance, find the height of the start point of the slide above the water.
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