At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.28 m, what is her speed at the bottom of the slide?

Answer 1

Use the fact that the kinetic energy gained (1/2)MV^2, will equal the gravitational potential energy lost, MgH.

Therefore V^2 = 2 g H

H is the vertical height and g is the acceleration of gravity.

Solve for V. It will be in m/s if g is in m/s^2