At an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and decends through a vertical height of 2.40 m, what is her speed at the bottom of the slide?

2 answers

The use of conservation of energy approach will tell you right away that
V = sqrt(2 g H)

loss of potential energy = M g H = gain in kinetic energy = (1/2) M V^2
Therefore 2gH = V^2
V = sqrt(2 g H)