Question

A student is completing a Punnett square for a trait (T/t) that is autosomal and inherited by the dominant allele. The father does not have the trait (tt) but the mother does (Tt). If they had two children, a son and a daughter, what would the completed Punnett square look like (i.e., would the son have the trait, would the daughter have the trait?)(1 point)
Responses

Each child would have a 100% chance of inheriting the trait.
Each child would have a 100% chance of inheriting the trait.

Each child would have a 0% chance of inheriting the trait.
Each child would have a 0% chance of inheriting the trait.

The son would inherit the trait and the daughter would not.
The son would inherit the trait and the daughter would not.

Each child has a 50% chance of inheriting the trait.

Answer 1

To determine the chances of the children inheriting the trait, we can complete a Punnett square for the parents' genotypes:

- Father: tt (homozygous recessive)
- Mother: Tt (heterozygous)

The possible gametes from each parent are:

- Father can only contribute: t
- Mother can contribute: T or t

The Punnett square would look like this:

```
T | t
-------------------
t | Tt (trait) | tt (no trait)
-------------------
t | Tt (trait) | tt (no trait)
```

From the Punnett square, we can see the offspring possibilities:

- 50% chance of Tt (trait)
- 50% chance of tt (no trait)

So, for each child (son and daughter), there is a 50% chance of inheriting the trait (T) and a 50% chance of not inheriting it (tt).

Thus, the correct response is:
**Each child has a 50% chance of inheriting the trait.**