Asked by Zulaiykherh
Using the method completing the square. Find the roots of this equation 4d^2= (d+4)(-d+12)
Answers
Answered by
Reiny
4d^2= (d+4)(-d+12)
4d^2 = -d^2 + 12d - 4d + 48
5d^2 - 8dd = 48
d^2 - (8/5)d = 48/5
d^2 - (8/5)d + 16/25 = 48/5 + 16/25
(d - 4/5)^2 = 256/25
d - 4/5 = ± 16/5
d = 4/5 + 16/5 OR d = 4/5 - 16/5
d = 4 or d = -12/5
4d^2 = -d^2 + 12d - 4d + 48
5d^2 - 8dd = 48
d^2 - (8/5)d = 48/5
d^2 - (8/5)d + 16/25 = 48/5 + 16/25
(d - 4/5)^2 = 256/25
d - 4/5 = ± 16/5
d = 4/5 + 16/5 OR d = 4/5 - 16/5
d = 4 or d = -12/5
Answered by
Zulaiykherh
Thank you for your much very needed help, really appreciate your kind gesture towards me @Reiny
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