Question
2x^2-x-28=0
Completing the square.
Completing the square.
Answers
Steve
2x^2-x-28 = 0
2(x^2 - 1/2 x) = 28
2(x^2 - 1/2 x + (1/4)^2) = 28 + 2(1/4)^2
2(x - 1/4)^2 = 225/8
(x - 1/4)^2 = 225/16
x - 1/4 = ±15/4
x = 1/4 ± 15/4
x = -7/2, 4
2(x^2 - 1/2 x) = 28
2(x^2 - 1/2 x + (1/4)^2) = 28 + 2(1/4)^2
2(x - 1/4)^2 = 225/8
(x - 1/4)^2 = 225/16
x - 1/4 = ±15/4
x = 1/4 ± 15/4
x = -7/2, 4
Ciara
Okay, so I also got the same answer using the Quadratic Formula. Is that okay to happen?
Steve
it better happen!
There is only one correct answer...
Of course, the problem said to complete the square.
There is only one correct answer...
Of course, the problem said to complete the square.