Asked by Ciara
2x^2-x-28=0
Completing the square.
Completing the square.
Answers
Answered by
Steve
2x^2-x-28 = 0
2(x^2 - 1/2 x) = 28
2(x^2 - 1/2 x + (1/4)^2) = 28 + 2(1/4)^2
2(x - 1/4)^2 = 225/8
(x - 1/4)^2 = 225/16
x - 1/4 = ±15/4
x = 1/4 ± 15/4
x = -7/2, 4
2(x^2 - 1/2 x) = 28
2(x^2 - 1/2 x + (1/4)^2) = 28 + 2(1/4)^2
2(x - 1/4)^2 = 225/8
(x - 1/4)^2 = 225/16
x - 1/4 = ±15/4
x = 1/4 ± 15/4
x = -7/2, 4
Answered by
Ciara
Okay, so I also got the same answer using the Quadratic Formula. Is that okay to happen?
Answered by
Steve
it better happen!
There is only one correct answer...
Of course, the problem said to complete the square.
There is only one correct answer...
Of course, the problem said to complete the square.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.