Question

A student is completing a Punnett square for a trait (T/t) that is autosomal and inherited by the dominant allele. The father does not have the trait (tt) but the mother does (Tt). If they had two children, a son and a daughter, what would the completed Punnett square look like (i.e., would the son have the trait, would the daughter have the trait?)(1 point) Responses Each child would have a 100% chance of inheriting the trait. Each child would have a 100% chance of inheriting the trait. Each child would have a 0% chance of inheriting the trait. Each child would have a 0% chance of inheriting the trait. The son would inherit the trait and the daughter would not. The son would inherit the trait and the daughter would not. Each child has a 50% chance of inheriting the trait.
Select One

Answer 1

To determine the genotypes of the children, we can set up a Punnett square using the alleles from the father and mother:

- Father: tt (homozygous recessive)
- Mother: Tt (heterozygous)

The Punnett square will look like this:

```
T t
+-----+-----+
t | Tt | tt |
+-----+-----+
t | Tt | tt |
+-----+-----+
```

From this Punnett square, we can analyze the possible genotypes of the children:

- 50% chance for Tt (which expresses the trait, since T is dominant)
- 50% chance for tt (which does not express the trait)

Thus, each child has a 50% chance of inheriting the trait.

The possible outcomes for the children (if we consider both a son and a daughter):
- The son could be either Tt (with the trait) or tt (without the trait).
- The daughter could also be either Tt (with the trait) or tt (without the trait).

Therefore, the correct response is: **Each child has a 50% chance of inheriting the trait.**