The student's work is not correct. Let's analyze the steps they took:
- They correctly wrote the expression as \(-6(4x - \frac{2}{13})\).
- The student then wrote \(-6(4x) + 6(-\frac{2}{13})\).
Here is where the mistake happens. When you distribute \(-6\) to both \(4x\) and \(-\frac{2}{13}\), you should multiply by \(-6\) in both cases:
\[ -6(4x) \text{ which gives } -24x \] \[ -6\left(-\frac{2}{13}\right) \text{ which gives } \frac{12}{13} \]
Thus, the correct distributed expression should have been: \[ -24x + \frac{12}{13} \]
The student mistakenly wrote \(6(-\frac{2}{13})\) as \(-\frac{12}{13}\) (instead of \(+\frac{12}{13}\)).
Therefore, the correct answer is:
B. No, the student should have multiplied 4x and -2/13 by -6.