A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest? (hint: remember force = mass x acceleration). (1 point)

Question

Responses

10 N
10 N

1.02 N
1.02 N

98 N
98 N

9.8 N
9.8 N

Answer 1

To find the normal force acting on the stone, we can use the formula for force:

\[ \text{Force} = \text{Mass} \times \text{Acceleration} \]

In this case, the mass of the stone is 10 kg, and the acceleration due to gravity is 9.8 m/s². Therefore, the force exerted by gravity on the stone (which is the weight of the stone) is:

\[ \text{Weight} = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest and there are no other vertical forces acting on it, the normal force (upward force) must balance the weight of the stone (downward force).

Thus, the normal force acting on the stone is also 98 N.

So, the correct answer is:

98 N