stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?

Answer 1

The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the stone is at rest, which means the normal force is equal in magnitude and opposite in direction to the gravitational force acting on the stone.

The gravitational force is given by the formula:

force = mass × acceleration

In this case, the mass of the stone is 10 kg, and the acceleration due to gravity is 9.8 m/s^2. Plugging these values into the formula, we get:

force = 10 kg × 9.8 m/s^2 = 98 N

So, the normal force exerted by the ground on the stone to keep it at rest is 98 Newtons.