A stone with a mass if 10kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s^2. What is the normal force acting on the stone, keeping it at rest?

9.8n
98n
1.02n
10n

1 answer

To find the normal force acting on the stone, we can use the formula:

\[ \text{Normal Force} = \text{Weight of the object} \]

The weight of the object can be calculated using the formula:

\[ \text{Weight} = \text{mass} \times \text{gravity} \]

Given that the mass of the stone is 10 kg and the acceleration due to gravity is 9.8 m/s²:

\[ \text{Weight} = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest and there are no vertical forces acting on it other than its weight and the normal force, the normal force must be equal to the weight of the stone.

Thus, the normal force acting on the stone is 98 N.