A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)

Responses

98 N

98 N

1.02 N

1.02 N

9.8 N

9.8 N

10 N

1 answer

To calculate the normal force acting on the stone, we need to consider that it is at rest and the only forces acting on it are its weight (due to gravity) and the normal force from the ground.

The weight of the stone can be calculated using the formula:

\[ \text{Weight} = \text{mass} \times \text{gravity} \]

Given that the mass of the stone is 10 kg and gravity is 9.8 m/s²:

\[ \text{Weight} = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is resting on the ground and not accelerating, the normal force must be equal in magnitude and opposite in direction to the weight of the stone to keep it at rest.

Thus, the normal force is:

98 N

So, the correct response is 98 N.