A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)

Question

Responses

98 N
98 N

9.8 N
9.8 N

1.02 N
1.02 N

10 N

Answer 1

To find the normal force acting on the stone, we can use the formula for the weight of the stone, which is given by:

\[ \text{Weight} (W) = \text{mass} (m) \times \text{gravity} (g) \]

Given that the mass \( m \) of the stone is 10 kg and the acceleration due to gravity \( g \) is 9.8 m/s², we can calculate the weight as follows:

\[ W = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest and not moving, the normal force (N) acting on it must be equal to the weight of the stone to balance the forces acting on it.

Thus, the normal force is:

\[ N = W = 98 , \text{N} \]

The correct answer is 98 N.