A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2. What is the normal force acting on the stone, keeping it at rest?(1 point)

Question

Responses

10 N
10 N

98 N
98 N

1.02 N
1.02 N

9.8 N

Answer 1

To find the normal force acting on the stone, we can use the formula that relates weight to force due to gravity:

\[ \text{Weight (W)} = \text{mass (m)} \times \text{acceleration due to gravity (g)} \]

Given:

• Mass (m) = 10 kg
• Acceleration due to gravity (g) = 9.8 m/s²

Calculating the weight:

\[ W = 10 , \text{kg} \times 9.8 , \text{m/s}^2 = 98 , \text{N} \]

Since the stone is at rest on the ground, the normal force (N) is equal to the weight of the object:

\[ N = W = 98 , \text{N} \]

Therefore, the normal force acting on the stone is 98 N.