v = 50 m/s
h = 100 m = x
x = 1/2 at^2
t = (square root) x/(1/2)
t = 4.51 s
Vi = 50 m/s so you have to find the final speed if you want to find the angle of projection, vi = 0 m/s i think cannot be zero
vf^2 = vi^2 + 2ad
I'm sorry you're going to have to look up this. Or maybe the other tutors here will help you. But I'm thinking you might have to include sin/speed to find the angle of projection
A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.
calculate:
a.the time of flight
b.the angle of projection
c.the range attained:
9 answers
45
T=gt,t=50;>100=150
velocity of stone=50m/s
height attained=100m
therefore,
time of flight=T=2Usin¤/g,
But time taken to get up to 100m=t1=Usin¤/g
..NOTE..
formula for time of flight=t1 was gotten from 2nd equation of motion which is equal to=S=UT+1/2AT SQUARED...
SUBSTITUTING THE GIVEN PARAMETERS,
S=100m
U=0
A=G=10ms
T=UNKNOWN=X
therefore,after working,
you will definetly get a value for t1 which would be approximately 4.something..in other to get total time of flight,T=2timest1...
coprehensively and secondly,
in other to get uhe angle of projection correctly,we apply the full formula total time of flight which has titan in it,after taking correct caculation,you will get the absolute angle of projection which is between 30 to 40,
lastly,you follow other protocols to get the range etc..for more answers to physics secondary questions,heres my number >08169373301
height attained=100m
therefore,
time of flight=T=2Usin¤/g,
But time taken to get up to 100m=t1=Usin¤/g
..NOTE..
formula for time of flight=t1 was gotten from 2nd equation of motion which is equal to=S=UT+1/2AT SQUARED...
SUBSTITUTING THE GIVEN PARAMETERS,
S=100m
U=0
A=G=10ms
T=UNKNOWN=X
therefore,after working,
you will definetly get a value for t1 which would be approximately 4.something..in other to get total time of flight,T=2timest1...
coprehensively and secondly,
in other to get uhe angle of projection correctly,we apply the full formula total time of flight which has titan in it,after taking correct caculation,you will get the absolute angle of projection which is between 30 to 40,
lastly,you follow other protocols to get the range etc..for more answers to physics secondary questions,heres my number >08169373301
8.94s, 64.43, 2oom
APPLY THE PARAMETERS,YOU HAVE T AS ZERO(0)
Answer t0 this question
That's not correct
I. Don't understand this