Just as long as anything else that goes up 100 meters and falls
Which is twice as long as it takes to fall 100 meters
h = (1/2) g t^2
100 = 4.9 t^2
t = 4.52 seconds to fall
so about 9 seconds
A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.Calculate:(a)the time of flight?
25 answers
time of fligt
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
am asking question a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m calculate (a)the range attained
(a)the angle of projection (b) the range attained
T=8.945
I don't get why it is multiplied by 2
how are we going to calculate the angle of projection and the range attained
Which Formular Will You Use To Get The Angle Of Projection?
Tether=sin-1(Tg/2u)
A STONE IS PROPELLED FROM A CATAPULT WITH A SPEED OF 500MS ATTAINS THE HEIGHT OF 100M.CALCULATE,a:THE TIME OF FLIGHT,b:THE ANGLE OF PROJECTION,c:THE RANGE ATTAINED.
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
I THINK ANONYMOUS MAY BE CORRECT
Thanks so much for solving this problem already, i appreciate u very much
Thanks so much i appreciate
Anonymous are right
How did you get the tita
Exactly how did you get the theta
pls how did u solve the angle of projection
A stone propeller from a catopon often a gift of 100m calculate
Yggdo
What is the formula used in time of flight
Thank you very well
thanks
A how do i calculate a stone propelled from a catapult with a speed of 50ms attains a height of 100m.calcute the time of flight
3 answers