A STONE OF MASS 20g IS RELEASE FROM A CATAPULT WHOSE RUBBER IS STRETCHED THROUGH 5cm IF THE FORCE CONSTANT OF THE RUBBER IS 200N/m CALCULATE THE SPEED WITH WHICH THE STONE LEAVE THE CATAPULT

Answer 1

energy stored in spring = (1/2) k x^2
= (1/2)(200)(.05)^2
= kinetic energy of stone = (1/2)(.020) v^2