A stone of mass 20g is release from a catapult whose rubber has been stretched through 4cm, if the force constant of the rubber is 200N/M .calculate the velocity with which the stone leaves the catapult.

Question

henry2, · Accepted Answer

F = 200N/m * 0.04m = 8 N. W = F*d = 8*0.04 = 0.32 J. Work = change in KE: W = 0.5M*V^2 = 0.32. 0.01*V^2 = 0.32, V =

R_scott · Answer

the energy stored in the rubber is ... 1/2 k x^2 ... 1/2 * 200 * .04^2 Joules with no losses (friction, etc.) , the stored energy becomes the stone's K.E 1/2 k x^2 = 1/2 m v^2 = 1/2 * .02 kg * v^2

faith · Answer

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Amaka Esther Ejikeme · Answer

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Aishat · Answer

Yes

Ayobami · Answer

Yes

horpheyhemhi · Answer

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omolara · Answer

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olajide mary · Answer

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suleiman · Answer

answer

Sophia · Answer

1/2KE^2=1/2mv^2 1/2*200*(0.05)^2=1/2*0.02*v^2 V^2=25 V=5m/s

Samson · Answer

A stone of mass 20g is release from a catapult whose rubber has been stretched through 4cm, if the force constant of the rubber is 200N/M .calculate the velocity with which the stone leaves the catapult.