so its average speed was 50m/s on the way up, so time= 2 seconds. (100/50)
I assume the height was 100m.
a stone is release from a catapult with a speed of 50m/s attain a height of 100m/s .Calculate the time of flight
2 answers
If vi in the y direction is 50 we can use different equations to find t
a=-9.8
v(yi)=50
I used this equation
v(y)=(vyi)+at
at the height of the trajectory y velocity is 0
0=50+-9.8t
solve for t, this is half the time in the air. so 2t=10.2sec
a=-9.8
v(yi)=50
I used this equation
v(y)=(vyi)+at
at the height of the trajectory y velocity is 0
0=50+-9.8t
solve for t, this is half the time in the air. so 2t=10.2sec
2 answers