A stone is propelled from a catapult with a speed of 50ms-1 ,attains a height of 100m calculate:
1.the time of flight
2.the angle of projection
3.the range
3 answers
Do one is solving
Y^2 = Yo^2+2g*h = 0.
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
Don't understand