A standard deck of cards has 52 cards divided into 4 suits, each of which has 13 cards. Two of the suits ($\heartsuit$ and $\diamondsuit$, called `hearts' and `diamonds') are red, the other two ($\spadesuit$ and $\clubsuit$, called `spades' and `clubs') are black. The cards in the deck are placed in random order (usually by a process called `shuffling'). What is the probability that the first two cards drawn from the deck are both red?

Answer 1

(26/52)+(25/51)

Answer 2

No, the second event is dependent on the first, so....
(26/52)(25/51) = .....

Answer 3

I bet Cody meant * not +

Answer 4

It is (26/52)(25/51) Which is equal to 25/102

Answer 5

its not correct

Answer 6

The correct answer is 25/102.
There are 26 red cards in the set, and 52 cards.
The first card has a
$1/2$ chance of being red and this question is without replacement, meaning it has a dependant equation, and so the next fraction in the equation will be $25/51$.
Now, we multiply $1/2$ and $25/51$, and get $25/102$.