A spring has a spring stiffness constant, k, of 420 N/m .

Question

1. How much must this spring be stretched to store 30 J of potential energy?

Answer 1

Potential energy = 30 J,
Spring stiffness constant k = 420 N/m
distance x = ?

Potential energy = 1/2*k*x^2
=> 30 = 1/2*420*x^2
=> x = √(30/210)
= 0.378 m