A spring has a spring stiffness constant k=9.5 N/m, how much must this spring be stretched to store 189.7 J of potential energy by applying a constant force of 1253.1?

Answer 1

Energy stored = (1/2) k x^2
189.7 = (1/2) (9.5) x^2
x^2 = 39.9
x = 6.32 meters
now can you do that with 1253.1 N ?
1253.1 = 8.5 x
x = 147 meters
so yes

Answer 2

is it 8.5 or 9.5? thank you btw

Answer 3

this is not the answer i was given