A spring 20cm long is stress to a 25cm by a load of 50n.what will be it new length when stress by 80n assuming that the elastic limit is not exceeded.

Answer 1

We can use the formula for stress and strain to solve this problem:

stress = force / area

strain = change in length / original length

Since the spring is stretched, we can assume that the area is constant. Therefore, we can use the stress to find the strain:

strain = stress / modulus of elasticity

where the modulus of elasticity is a constant that depends on the material of the spring.

Let's assume that the modulus of elasticity for this spring is 20 N/cm². Then, we can calculate the strain caused by the first load of 50 N:

strain = 50 N / (20 N/cm²) = 2.5 cm/cm

This means that the spring increased its length by 2.5 cm for every 1 cm of its original length. Therefore, its new length under a load of 80 N would be:

change in length = strain * original length * force

change in length = (2.5 cm/cm) * (20 cm) * (80 N)

change in length = 400 cm

new length = original length + change in length

new length = 20 cm + 400 cm

new length = 420 cm

Therefore, the new length of the spring under a load of 80 N would be 420 cm, assuming that the elastic limit is not exceeded.