Asked by Anonymous

a spring 20cm long is stretched to 25cm by a load of 50N. what will be its lenght when stretched by 100N assuming that the elastic limit is not reached
Answered by Henry
k = 50N/(25-20)cm = 10N/cm.

Length = 20cm + 100N*1cm/10N = 30 cm.
Answered by AMARACHI
30CM
Answered by Kabiru
ANSWER
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