Question
a spring 20cm long is stretched to 40cm by a load of 50n .what is
1.the length when stretched by 100n
2.what is the work done when stretched by 100n
1.the length when stretched by 100n
2.what is the work done when stretched by 100n
Answers
1. twice the force, so twice the stretch
2. F = kx, so k = 50N/20cm = 2.5 N/cm
W = 1/2 kx^2
2. F = kx, so k = 50N/20cm = 2.5 N/cm
W = 1/2 kx^2
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