Question

A spring 20cm long is stretched to 25cm by a load of 50newton.what will be it's length by 100newton.

Answers

Assuming that the spring follows Hooke's law (that the force applied is directly proportional to the extension of the spring), we can set up a proportion to solve for the new length:

(load 1/load 2) = (extension 1/extension 2)

Where:

load 1 = 50 N
extension 1 = 25 cm - 20 cm = 5 cm

load 2 = 100 N
extension 2 = ?

Plugging in the values:

(50 N/100 N) = (5 cm/extension 2)

Simplifying and solving for extension 2:

(1/2) = (5 cm/extension 2)

Multiplying both sides by extension 2:

extension 2/2 = 5 cm

extension 2 = 10 cm

Therefore, the length of the spring by 100 N will be 20 cm + 10 cm = 30 cm.

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