Assuming that the spring follows Hooke's law (that the force applied is directly proportional to the extension of the spring), we can set up a proportion to solve for the new length:
(load 1/load 2) = (extension 1/extension 2)
Where:
load 1 = 50 N
extension 1 = 25 cm - 20 cm = 5 cm
load 2 = 100 N
extension 2 = ?
Plugging in the values:
(50 N/100 N) = (5 cm/extension 2)
Simplifying and solving for extension 2:
(1/2) = (5 cm/extension 2)
Multiplying both sides by extension 2:
extension 2/2 = 5 cm
extension 2 = 10 cm
Therefore, the length of the spring by 100 N will be 20 cm + 10 cm = 30 cm.
A spring 20cm long is stretched to 25cm by a load of 50newton.what will be it's length by 100newton.
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