A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.850 m/s at an angle of 34.3° above the table, and it lands on the magazine 0.0780 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

Answer 1

Vi up = .85 sin 34.3 = .479 m/s

h = 0 + Vi t - 4.9 t^2

h = .479(.078) - 4.9(.078)^2

in meters, multiply by 1000 to get mm