Answers by visitors named: Steven

P.S. I understand the mechanisms of E1, E2, and dehydrohalogenation. I just don't know how to find out whether an alkyl halide undergoing dehydrohalogenation will follow an E1 or an E2 reaction.

how do i find gravitational potential energy without being given the height?

1) I get it, except for lim (-1)^(n) = ? n-> +infinity is infinity even or odd? This is important because the result determines wheter the series that i was given is convergent or divergent. 2) in another excercise I encauntered the following problem: is the following calculation with infinity allowed?: lim (ln (n))^(1/n) = (ln (inf.))^(0)=1 n-> +inf. Again txs for answering.

Factor the trinomial c^2+5c+6

Well i believe it is bc H20 needs alot of energy to bc a gas bc of the molecular bonds on it, while CO2 requires less energy to become a gas so that is why it becomes a gas at room temp

I got 1)Potassium persulfate 2)persulfate ion 3)Sodium thiosufate 4)thiosulfate ion

The mol mass calculated would be higher than expected. but when we are measuring the pure cyclohexane's freezing point, this wouldn't matter right?? The freezing point would be the same no matter what the volume of solvent.

Thank you! I thought I was going crazy because I wasn't able to an eigenfunction since 1st deriv. would be = cos(x)*e^(ax) + a*sin(x)*e^(ax) which is definitely not an eigenfunction of the operator.

I'll also like to thank Dr. Physics for helping me last time :)

You are correct DrBob. Error on my part.

But for Nb2+ where it is 4d^3 Shouldn't L be D instead of F? Like p^2 in carbon, L = P And in s^2, L = S ------ Or am I going about this the wrong way?

what about Nb2+ then? it has 8 electrons it occupies 2, 1, 0, -1, -2 so would that make L = 0 which is S?

Thank you Dr Bob. Yes, I am seriously confusing myself haha As far as the 4d8 is concerned, I was referring to Ni2+ it has 8 electrons it occupies 2, 1, 0, -1, -2 so would that make L = 0 which is S? Sorry for the confusion. I greatly appreciate you staying and helping me despite my many errors.

OHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH. if it was 8e- in d orbitals (5 of em) it would be +2 +1 0 -1 -2 for up spin , then +2 +1 and 0 for down spin! therefore, total is 3 and L=3!!!! I hope this is correct!

Dr Bob, Thank you so much!! You have taught me something in mere minutes that my professor failed to do in a single lecture. And thank you again for the web site. I had no idea such a site existed! I wish there was a karma/rep system :) thanks again

To summarize my messy post, I am unsure how to write my final answer

Solve for b2: A=1/2h(b1+b2)

So would the ordered pair be (1,4)?

Kinematics Equations: Vx1 = Vx0 + axΔt (Vx1)^2 = (Vx0)^2 + 2axΔx Δx = Vx0Δt + ½ ax(Δt^2) Had the distance from the intersection when braking begins not been given: Remaining distance = 140.0 m Current Velocity = 14.8 m/s Reaction time = 0.440 s Find distance from intersection when breaking begins: 140.0 m - [14.8 m/s (0.440 s)] = 133.488 = 133. 488 m. Find what acceleration will bring you to rest as you just reach the intersection: Use the second kinematics equation, rearrange the variables to get "ax" by itself on one side: (Vx1)^2 = (Vx0)^2 + 2axΔx = V(Vx1)^2 - (Vx0)^2 = 2axΔx = [1/(2Δx)] [(Vx1)^2 - (Vx0)^2] = ax So: ax = [1/(2Δx)] [(Vx1)^2 - (Vx0)^2] Now plug in quantities for the known variables: ax = Brake acceleration = ? m/s^2 Δx = Distance to stop = 133.488 m Vx1 = Final Velocity = 0.00 m/s Vx0 = Initial Velocity = 14.8 m/s ax = {1/[2(133.488 m)]} {[0.00 m/s]^2 -[14.8 m/s]^2} ax = -0.82044828 m/s^2 Final answer (significant figures): ax = -0.820 m/s^2 -------------------------------------- Use the first kinematics equation to determine how long it will take you to stop: Vx1 = Vx0 + axΔt You can rearrange the equation to get Δt by itself, or just plug in what you know: 0.00 m/s = 14.8 m/s + [(-0.82044828 m/s^2)(Δt) -14.8 m/s = (-0.82044828 m/s^2)(Δt) Δt = (-14.8 m/s)/(-0.82044828) Δt = 12.14263454 Final answer (significant figures): Δt = 12.1 s ------------------------------------ Hope that helped- keep those kinematic equations handy (or, memorize them)!

That's not entirely correct... That would only be true if the rifle was fired horizontally, giving the x component 460 m/s towards the target. However, that 460 m/s has some UPWARD y component too, reducing the x component by some amount... Thanks, Steven

I would like to forget the upward component, as the object IS in fact a bullet fired at a fast velocity from a gun towards a target not too far away. However, we're graded on the correctness of our problem solving. And, additionally, this factor WOULD become an issue if we were firing a marshmallow gun or a pea shooter at this distance, or if you were firing a sniper rifle at a target over a mile away. Thanks, Steven

Kinematics Equations: Vx1 = Vx0 + axΔt (Vx1)^2 = (Vx0)^2 + 2axΔx Δx = Vx0Δt + ½ ax(Δt^2) Using the second kinematics equation, we can solve for Δx. (Vx1)^2 = (Vx0)^2 + 2axΔx Plug in what you know: (45 m/s)^2 = (0 m/s) + 2(9.8m/s^2)(? m) 2025 m^2/s^2 = (19.6 m/s^2)(? m) (? m) = (2025 m^2/s^2)/(19.6 m/s^2) ? m = 103.3163265 (sig figs) = 100 m Δx = 100m ----------------------------------- Using the first kinematics equation, we can solve for Δt. Vx1 = Vx0 + axΔt Plug in what you know: Vx1 = Vx0 + axΔt 45 m/s = 0 m/s + (9.8 m/s^2)(Δt) Δt = (45 m/s)/(9.8 m/s^2) Δt = 4.591836735 (sig figs) = Δt = 4.6 s Let me know if that helped you!

The speed at which the two objects are approaching each other (from the trains' perspective) is 95 km/h (x 2) = 190 km/h. If they are 7.5 km apart at first, you can set up a proportion: 190 km 7.5 km ------ = --------- 1 hr x hr Cross-multiply the terms and set them equal to each other. (190 km)(x hr) = (7.5 km)(1 hr) Divide both sides by (190 km). (190 km)(x hr) = (7.5 km)(1 hr) -------------- -------------- 190 km 190 km x hr = (7.5 kmh)/190 km x hr = 0.03947368421 hr. (sig figs = 0.039 hr) The unit of hr. may not be very useful in this case, so let's convert hrs to min using dimensional analysis: 0.03947368 hr 60 min ------------- x ------------ 1 1 hr = 2.36 minutes (sig figs = 2.4 minutes) Hope this helps!

Velocity is a vector quantity, meaning it has both magnitude and direction. Acceleration is the rate of the change of velocity. Therefore, if the speed changes, the object is accelerating (whether it speeds up or slows down). ALSO- if the object is changing direction, the object is accelerating. Car A is moving at a constant speed and is not changing direction. Car B is moving at a constant speed and is changing direction.

Can you figure it out now?

For question number 2. The answer is D right?

For Part B, do (340+200)/2=270 rpm to find the average rpm during acceleration. Then divide this answer by 60 seconds to find the average revolutions per second during acceleration 270/60=4.5 rev/sec. Multiply this answer by the amount of seconds it takes for it to accelerate and you will have your answer 4.5*5.92=26.64 rev.

Could you possibly give me a link to a more detailed picture? For example one that outlines each lobe and depicts more of the internal anatomy of the sheep's lung.

Need a more detailed picture of the sheep's pluck...lungs, trachea, and heart.

Thank you for your inputs :)

Thank you for your help! :) Im not a native english speaker and havent written an essay . I would really like some inputs. :)

In what ways can i improve this? more examples?

Why is the energy for high 2/5 of the energy for the low.

auren and Andrew left Austin at the same time. Lauren traveled east at an average speed of 50 miles per hour. Andrew traveled west at an average speed of 65 miles per hour. How many hours of driving does it take for the two to be at least 500 miles apart? Write an inequality to model this situation and give the solution rounded to the nearest hundredth. There are directions for how to type math characters in the Resource Center that will show you show to enter your equations.

Well if you multiply the static and the kinetic friction and add gravity to it you get the minimum magnitude. PhD in Physics

Mass = Density x Volume M=1.11g/cm^3 x 26.5 liters Mass = 29.425 Kg

Ok so i'm confused because T=273K is already in Kelvin.

Bonjour, Voici la réponse à tes questions 1) un ventillateur 2) le maillot de bain 3) un "dessus de lit" chaud 4) dans la bibliothèque 5) Dans l'armoire 6) des rideaux 7) Dans la salle de bain, dessus le lavabo 8) une gazinière

68/4= 17 (one side of square) area of square is the side^2 Answer:289 cm^2

plug 3 in for y 4x+2(3)=22 4x+6 =22 -6 -6 4x =16 ----------- 4 4 x = 4 Final Answer D; x=4 hope this helped

you need to plug the x value in the coordinate in to see if you get the coresponding y value Answer is A becuse: 3(0)-1 = -1 3(2)-1 = 5 3(5)-1 = 14

.3048 * 2 = .6096m/min then multiply by 60 to get into hours Final Answer: 36.576 meters/hour

divide everything by 6 , 3 min 6 seconds

Write it out

True

$72,000

i think we will get from your way damon h be about 15.68 which is wrong..

no no your correct but correct answer will bet putting h-3 in place of h..

how can i give the link ??

Yeah it is !

i mean f^(5)(x)=f(f(f(f(f(x))))).

Suppose that you are dropping off at a large mall without money and merely wander around looking at stores and displays. Later, someone asks you were a particular store is located in the mall. The fact that you direct the person to the store indicates that ______________ has occurred. a. behaviour modification. b. partial learning. c. stimulus training. d. latent learning.

a host of golden daffodils

Sexual arousal in human begins is different from that of other animals. It is clear that human sexual arousal can occur:

1 In Psychology, the study of personality focuses on: a. change. b. stability. c. external factors. d. learning factors.

Are you sure that is the variance. I got .14

4 The big Five in personality theories refers to which of the following? a. a set of functional traits such as neuroticism and openness to experiences. b. the group of personality theorists who criticized Freud's theory as too sexual. c. The effect of positive reinforcement on requiring new behaviors. d. the number of stages in Freud's theory of development.

How would you check the Z table for the first problem?

5 quarters (1.25)+23 dimes(2.30)

Ignore this one, I accidently posted a second one

Along with this question, how would you find the area of the outer-part of a racing track?

one of those oval shaped, racecar/track and field tracks

Ok, thanks!

Radiation: radiation is the transfer of energy along electromagnetic waves like light waves and radio waves Conduction: conduction is the transfer of heat between objects or substances that are in direct contact with each other Convection: convection is the transfer of heat by movement through a medium like air over a liquid. It is the primary method of heat transfer through gases

and also how? (if it even does)

P.S. Double Bogey +2 Bogey +1 Par 0 Birdie −1 Eagle −2 (you might need this)

Never mind, I figured it out myself!

A) 1/4 B) 1.25 pounds C) 8 Ounces (oz)=1 pound,approx 1.6 or 1.7 pounds per bird feeders. See if you can figure this on your own

All I'm looking for is confirmation that I correctly solved the problem. I know that I can use the formula: λ(wavelength) = v/f When I put in the numbers it gives me 5.666666666666667, which I then round up to 5.7. Is 5.7m the correct answer?

thanks

youre right i agree

yes its hard to pick between b and d.

HELP PLS I NEED TO DO HOMEWORK.

your welcome

i would add "Many woman suffer but Ida Tarbell changed that".

what happens to the volume of a rectangle if you multiply the length, the width, and the height by 2?

7x7x2=28 cubic inches

YES good job! Nice Essay! i would give it an A+

0.30 rounded

help MS.SUE

13.36 m/s^2

Vx=Ux+at Vx=16.1-(.65*9.81)(1.2) Vx=8.4482

truck drivers

509.7M

nvm I solved it

ahhh thanks but just a tad late lol, due already

Damon, Thank you so much

Thanks Ms Sue will start off my assignment soon

THE OTHER CONNEXUS PERON IS RIGHT!@!!!

The amplitude is given in the equation = .30

a.Project A Payback period Year 1 + Year 2 + Year 3 = $60,000 Year 4 + $20,000 Initial investment = $80,000 Payback=3 years + ($20,000 / 30,000) Payback =3.67 years Project B Payback period $50,000/ $15,000 = 3.33 years B. Project A CF0 = -$80,000; CF1= $15,000; CF2= $20,000; CF3= $25,000; CF4= $30,000; CF5 =$35,000 Set I = 13% Solve for NPVA = $3,659.68 Project B CF0 =-$50,000; CF1 = $15,000; F1 = 5 Set I= 13% Solve for NPVB = $2,758.47 c. Project A CF0=-$80,000; CF1 = $15,000; CF2= $20,000; CF3= $25,000; CF4=$30,000; CF5= $35,000 Solve for IRRA= 14.61% Project B CF0=$50,000; CF1= $15,000; F1=5 Solve for IRRB= 15.24% D. It's a Graph. (You must Make It) Data for NPV Profiles NPV Discount Rate A B 0% $45,000 $25,000 13% $3,655 2,755 14.6% 0 — 15.2% — 0 Intersection—approximately 14% If cost of capital is above 14%, conflicting rankings occur. The calculator solution is 13.87%. E. Both projects are acceptable. Both have similar payback periods, positive NPVs, and equivalent IRRs that are greater than the cost of capital. Although Project B has a slightly higher IRR, the rates are very close. Because Project A has a higher NPV, accept Project A.

2 tens 5 hundreds

1. Electrons 2. Atomic Model 3. Covalent Bond 4. Chemical bond 5. Either energy level or shell 6. Atomic theory 7. Atomic number Your answers are correct though I'm not sure about number 5.

What regulates the electronic media, except the Internet?

Can someone explain how he got to this conclusion? I understand he answer and everything, but if you had to show work what would you do?

I believe it's like: y-4=4x+3y y-4=-(9-x) 4x+3y=-(9-x)

Jane will win at least $5

Would it be A then?

14%

Are u sure u r right