A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.890 m/s at an angle of 33.6° above the table, and it lands on the magazine 0.0750 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

asked by Anonymous

13 years ago

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1 answer

hf= vivert*t-g t^2

vivert= .89sin33.6 solve for hf.

answered by bobpursley

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Question

A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is 0.890 m/s at an angle of 33.6° above the table, and it lands on the magazine 0.0750 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

1 answer

hf= vivert*t-g t^2

vivert= .89sin33.6 solve for hf.

bobpursley · Answer

hf= vivert*t-g t^2 vivert= .89sin33.6 solve for hf.