A soccer ball is kicked with a speed of 9.95m/s at an angle of 35.0∘ above the horizontal.If the ball lands at the same level from which it was kicked, how long was it in the air?

Answer 1

velocity up ;9.95sin35

hf=hi+vi*t-1/2 g t^2

hf, hi=0
solve for time t.

Answer 2

0 = 0 + Vi t - 4.9 t^2

Vi = 9.95 sin 35 = 5.71
so
0 = 5.71 t - 4.9 t^2
t = 0 or t = 1.16
t = 0 was zero height when it started
t = 1.16 seconds is zero height when it landed