Vo = 25m/s[20o].
Xo = 25*Cos20 = 23.5 m/s.
Yo = 25*sin20 = 8.55 m/s.
Y = Yo + g*Tr = 0.
8.55 - 9.8Tr = 0, Tr = 0.873 s. = Rise time.
Y^2 = Yo^2 + 2g*h = 0.
(8.55)^2 - 19.6h = 0, h = 3.73 m. Above the cliff.
0.5g*Tf^2 = 3.73+8.4
4.9Tf^2 = 12.13, Tf = 1.57 = Fall time.
Dx = Xo(Tr+Tf) = Hor. disp.
A soccer ball was kicked off a cliff that was h = 8.4 m above the ground. The ball was kicked at a speed of 25 m s-1 and an angle of 20 to the horizon.
What is magnitude of the horizontal displacement of the ball? Use g = 9.8 m s-2.
proper equation and help plz
1 answer
1 answer