A sequence of polynomials gk(x) is defined recursively as follows.
g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
4 answers
941
sorry, but wrong answer...
repeating the question again ->
A sequence of polynomials gk(x) is defined recursively as follows:
g0(x)=x
gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
repeating the question again ->
A sequence of polynomials gk(x) is defined recursively as follows:
g0(x)=x
gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
634
That's wrong. I thint, that should be 925.
0 answers