A sequence of polynomials gk(x) is defined recursively as follows.

g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)

Find the last three digits of the coefficient of x^2 in g299(x).

4 answers

941
sorry, but wrong answer...

repeating the question again ->

A sequence of polynomials gk(x) is defined recursively as follows:

g0(x)=x

gk+1(x)=gk(x^2+2x)−gk(x)

Find the last three digits of the coefficient of x^2 in g299(x).
634
That's wrong. I thint, that should be 925.