A sample of potassium hydrogen oxalate, KHC2O4, weighing 0.717 g, was dissolved in water and titrated with 18.47 mL of an NaOH solution. Calculate the molarity of the NaOH solution.

Answer 1

First, determine the molarity of KHC2O4:

0.717g*(1 mol/128.12g)=moles of KHC2O4

18.47 mL=0.01847L

Molarity of KHC2O4=moles of KHC2O4/0.01847L

The reaction is a 1 mole to 1 mole reaction. Therefore, moles of KHC2O4=moles of NaOH.

So, Molarity of KHC2O4=Molarity of NaOH

***Answer contains three significant figures.

Answer 2

0.185